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Max Consecutive Ones - Given a binary array nums, return the maximum number of consecutive 1's in the array. Example 1: Input: nums = [1,1,0,1,1,1] Output: 3 Explanation: The first two digits or the last three digits are consecutive 1s.
Jun 21, 2022 · Maximum consecutive one’s (or zeros) in a binary circular array. Given a binary circular array of size N, the task is to find the count maximum number of consecutive 1’s present in the circular array. The last 4 and first 2 positions have 6 consecutive ones. A Naive Solution is create an array of size 2*N where N is size of input array.
Sep 1, 2023 · Output. The length of the longest consecutive 1s in the binary representation is: 4. The time complexity of this algorithm is O (log n), where n is the given integer, since we iterate through the bits of the integer. The space complexity is O (1), since we only use constant extra space to store the variables max_len and cur_len.
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Apr 20, 2019 · The maximum number of consecutive 1s is 3. Note: The input array will only contain 0 and 1. The length of input array is a positive integer and will not exceed 10,000. The solution use Kadane algorithms. class Solution: def findMaxConsecutiveOnes(self, nums: "List[int]") -> int: loc_max = glo_max = 0. for i in range(len(nums)):
Nov 18, 2020 · When the count of 0’s becomes more than ‘K’ shorten the subarray by incrementing the left pointer ‘l’ so that the count of 0’s in subarray [l,r] becomes equal to ‘K’. At every step update the length of the longest subarray found so far, print this value at the end. Practice maximum consecutive ones coding problem.
Problem: Find the Maximum Consecutive One's in Array. Given a binary array consists of 0's and 1's. Find the maximum number of consecutive 1's in that Array. Ex: Array A=[1,1,0,0,1,1,1,0,0,1,1,1,1] Above array contains. 2 - consecutive 1's. 3 - consecutive 1's. and. 4 - consecutive 1's. the maximum value among 2, 3, 4 is 4. The output for the ...
