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  1. The count of s - k in the counter tells us how many subarrays (ending right before the current index) have a sum that would complement the remainder of the current sum to reach k . This is done by ans += counter[s - k]. Update the counter with the new cumulative sum. Increment the existing value of counter[s] by 1, or set it to 1 if s is not ...

  2. Dec 8, 2023 · When the subarray sum is equal to k we will increment the count variable. For the above example: Array = [1,2,3,2,1,4] k = 5. Output = 3. The subarray with starting index i = 1 to ending index j = 2 has a sum equal to k. The subarray with starting index i = 2 to ending index j = 3 has a sum equal to k.

  3. Sep 1, 2022 · The task is to check if there exists any subarray with K elements whose sum is equal to the given sum. If any of the subarray with size K has the sum equal to the given sum then print YES otherwise print NO. Examples : k = 4, sum = 18. Output: YES. Input: arr[] = {1, 4, 2, 10, 2, 3, 1, 0, 20} k = 3, sum = 6.

  4. Mar 27, 2023 · In summary, the subarray sum equals k problem is a fundamental problem in computer science that has practical applications in various domains. It can be solved using different techniques, and the choice of technique depends on the problem requirements and the size of the input array. Understanding the Basics of the Subarray Sum Equals K Problem

  5. Algorithm For Subarray sum equals k. create a cumulative sum array sum [] of length n+1 (n = size of of input array arr [] ). assign sum [0] = 0, sum of zero elements. Iterate over arr [] and assign sum [i] = sum of elements in range [0,i-1]. Run an outer loop in range [0,n-1].

  6. Subarray Sum Equals K - Given an array of integers nums and an integer k, return the total number of subarrays whose sum equals to k. A subarray is a contiguous non-empty sequence of elements within an array.

  7. Apr 22, 2020 · This video explains a very important programming interview problem which is to count the number of subarrays in a given array with sum exactly equals to K. T...

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