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  1. 169. Majority Element. Easy. Given an array nums of size n, return the majority element. The majority element is the element that appears more than ⌊n / 2⌋ times. You may assume that the majority element always exists in the array. Example 1: Input: nums = [3,2,3] Output: 3. Example 2: Input: nums = [2,2,1,1,1,2,2] Output: 2. Constraints:

  2. May 17, 2016 · 169. Majority Element Description. Given an array nums of size n, return the majority element. The majority element is the element that appears more than ⌊n / 2⌋ times. You may assume that the majority element always exists in the array. Example 1: Input: nums = [3,2,3] Output: 3 Example 2: Input: nums = [2,2,1,1,1,2,2] Output: 2 Constraints:

  3. In-depth solution and explanation for LeetCode 169. Majority Element in Python, Java, C++ and more. Intuitions, example walk through, and complexity analysis. Better than official and forum solutions.

  4. class Solution: def (, nums: List [ ]) ->: ans = count = 0 for num nums: if count == 0: ans = num count += ( 1 if num == ans else - 1) return ans. LeetCode Solutions in C++20, Java, Python, MySQL, and TypeScript.

  5. Given an array nums of size n, return the majority element. The majority element is the element that appears more than ⌊n / 2⌋ times. You may assume that the majority element always exists in the array. Example 1: Input: nums = [3,2,3] Output: 3. Example 2: Input: nums = [2,2,1,1,1,2,2] Output: 2. Constraints:

  6. Dec 4, 2022 · A majority candidate is defined as more than 50%. So in a given array of integers you have different methods to find it. Watch the video to learn 4 ways how you can start and ultimately arrive at...

  7. Jan 13, 2024 · LeetCode 169. Majority Element. Find the element that appears more than n/2 times in a list. Solution Approach: Two Pointer. 1) Traverse the entire list and create a dictionary. 2) Return the value in the dictionary that appears more than n/2 times.

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