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  1. Learn polynomials in one variable, zeroes, remainder theorem, factorisation and algebraic identities with NCERT solutions for Class 9 Maths Chapter 2. Download PDF, access exercise-wise solutions and get ready for CBSE exams.

    • RT Solutions For Class 9 Maths Chapter 2 Polynomials Ex 2.2
    • RT So1utions For C1ass 9 Maths Chapter 2 Polynomials Ex 2.3
    • RT So1utions For Class 9 Maths Chapter 2 Polynomials Ex 2.4
    • RT Solutions For Class 9 Maths Chapter 2 Polynomials Ex 2.5

    Question 1. Find the value of the polynomial 5x – 4x2 + 3 at (i) x = 0 (ii) x = – 1 (iii) x = 2 Solution: 1et p(x) = 5x – 4x2 + 3 (i) p(0) = 5(0) – 4(0)2 + 3 = 0 – 0 + 3 = 3 Thus, the value of 5x – 4x2 + 3 at x = 0 is 3. (ii) p(-1) = 5(-1) – 4(-1)2 + 3 = – 5x – 4x2 + 3 = -9 + 3 = -6 Thus, the value of 5x – 4x2 + 3 at x = -1 is -6. (iii) p(2) = 5(2)...

    Question 1. Find the remainder when x3 + 3x2 + 3x + 1 is divided by (i) x + 1 (ii) x – (iii) x (iv) x + π (v) 5 + 2x Solution: Let p(x) = x3 + 3x2 + 3x +1 (i) The zero of x + 1 is -1. ∴ p(-1) = (-1)3 + 3(-1)2 + 3(-1) +1 = -1 + 3- 3 + 1 = 0 Thus, the required remainder = 0 (ii) The zero of is Thus, the required remainder = (iii) The zero of x is 0. ...

    Question 1. Determine which of the following polynomials has (x +1) a factor. (i) x3+x2+x +1 (ii) x4 + x3 + x2 + x + 1 (iii) x4 + 3x3 + 3x2 + x + 1 (iv) x3 – x2 – (2 +√2 )x + √2 Solution: The zero of x + 1 is -1. (i) Let p (x) = x3 + x2 + x + 1 ∴ p (-1) = (-1)3 + (-1)2 + (-1) + 1 . = -1 + 1 – 1 + 1 ⇒ p (- 1) = 0 So, (x+ 1) is a factor of x3 + x2+ x...

    Question 1. Use suitable identities to find the following products (i) (x + 4)(x + 10) (ii) (x+8) (x -10) (iii) (3x + 4) (3x – 5) (iv) (y2+ ) (y2– ) (v) (3 – 2x) (3 + 2x) Solution: (i) We have, (x+ 4) (x + 10) Using identity, (x+ a) (x+ b) = x2 + (a + b) x+ ab. We have, (x + 4) (x + 10) = x2+(4 + 10) x + (4 x 10) = x2+ 14x+40 (ii) We have, (x+ 8) (...

  2. constants. Similarly, quadratic polynomial in y will be of the form ay2 + by + c, provided a ≠ 0 and a, b, c are constants. We call a polynomial of degree three a cubic polynomial. Some examples of a cubic polynomial in x are 4x3, 2x3 + 1, 5x3 + x2, 6x3 – x, 6 – x3, 2x3 + 4x2 + 6x + 7. How many terms do you think a cubic polynomial in one ...

    • 26 min
    • Term. In the polynomial, each expression is called a term. Suppose x2 + 5x + 2 is polynomial, then the expressions x2, 5x, and 2 are the terms of the polynomial.
    • Coefficient. Each term of the polynomial has a coefficient. For example, if 2x + 1 is the polynomial, then the coefficient of x is 2.
    • Types of Polynomial. A polynomial of 1 term is called a monomial. Example: 2x. A polynomial of 2 terms is called a binomial. Example: 5x + 2. A polynomial of 3 terms is called a trinomial.
    • Constant Polynomial. Real numbers can also be expressed as polynomials. 3, 6, and 7 are also polynomials without any variables. These are called constant polynomials.
  3. 2 days ago · Learn about polynomials, their degrees, zeros, operations, and factor theorems with Vedantu's NCERT solutions for Class 9 Maths Chapter 2. Access exercise-wise solutions, PDF download, video links, and more resources for CBSE students.

  4. Learn about polynomials in one variable, their degree, zeroes, factorisation and division. Find NCERT exercise questions and examples with solutions and videos at Teachoo.

  5. Apr 30, 2024 · Find online and offline solutions for CBSE and UP Board exams based on NCERT books for class 9 maths chapter 2 polynomials. Learn the definitions, properties, types and examples of polynomials with videos and important terms.

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