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Fringe width $$\beta \dfrac{D\lambda }{d}$$ So, $$\beta$$ depends on : (i) Wavelength $$\lambda$$ (ii) Distance of slite from screen , D (iii) Distance between slits 2 d
Jun 28, 2024 · The fringe width is independent of the order of the fringe. We can also see from the expression that it is directly proportional to the wavelength of the source. That is the fringes produced for red light will be wider than the fringes produced by blue light.
The distance between the slit and the bi-prism and that of between bi-prism and screen each is 0.4 m.The obtuse angle of bi-prism is 179 0 and refractive index is 1.5.If the fringe width is 1.8 × 10 − 4 m then the distance between imaginary sources will be
View Solution. Q 5. If The mirror is shifted towards left then how does the fringe pattern on screen change? (A) fringe width decreases and the region in which interference is formed shifts downward. (B) fringe width decreases and the region in which interference is formed shift upwards. (C) fringe width does not change and the region in which ...
Jun 12, 2015 · 2. I have superimposed a ruler on top of a photograph of the diffraction pattern due to a single slit. To get visible images of fringes which are further out from the centre the central fringes have been overexposed and so the dark fringes look very narrow. You will note that the outer fringes do appear to be narrower but the fringe separation ...
Fringe width is directly proportional to the wavelength of light used. Therefore, fringe width decreases. Explanation for the incorrect options: In case of option A: In water wavelength of the light decreases hence fringe width decreases. In case of option C: Distance between slits and screen and slit width is unchanged but wavelength decreases.
In a Young's double slit experiment, the fringe width is found to be 2 mm, when light of wavelength 6000 ˚ A is used. find the change in fringe width if the whole apparatus is immersed in water of refractive index 1.33.
