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Can you solve this real interview question? Climbing Stairs - You are climbing a staircase. It takes n steps to reach the top. Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top? Example 1: Input: n = 2 Output: 2 Explanation: There are two ways to climb to the top. 1.
class Solution: def climbStairs (self, n: int)-> int: # dp[i] := the number of ways to climb to the i-th stair dp = [1, 1] + [0] * (n-1) for i in range (2, n + 1): dp [i] = dp [i-1] + dp [i-2] return dp [n]
Can you solve this real interview question? Climbing Stairs - Level up your coding skills and quickly land a job. This is the best place to expand your knowledge and get prepared for your next interview.
Oct 9, 2023 · Climbing Stairs (LeetCode #70): You are climbing a staircase. It takes n steps to reach the top. Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?
Given a staircase with n steps, we need to find the total number of distinct ways to climb it by taking 1 or 2 steps at a time. Sure, this can be done by a brute force method and finding all the...
You are climbing a staircase. It takes n steps to reach the top. Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top? Example 1: Input: n = 2 Output: 2 Explanation: There are two ways to climb to the top. 1 step + 1 step; 2 steps; Example 2:
Climbing Stairs. Easy. You are climbing a staircase. It takes n steps to reach the top. Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top? Example 1: Input: n = 2. Output: 2. Explanation: There are two ways to climb to the top. 1. 1 step + 1 step. 2. 2 steps. Example 2: Input: n = 3. Output: 3.
Apr 25, 2021 · You are climbing a staircase. It takes n steps to reach the top. Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top? Solution: Time Complexity : O(n) Space Complexity: O(n)
Solution 1 - Dynamic Programming: Recursive. class Solution { public int climbStairs ( int n) { int [] cache = new int [ n + 1 ]; return climbStairs ( n, cache ); } private int climbStairs ( int n, int [] cache) { if ( n < 0) { // this can happen due to our recursive calls return 0 ; } else if ( n == 0 || n == 1) {
Approach 1: Fibonacci Series. We can apply the concept of Fibonacci Numbers to solve this problem. The number of ways to reach the n^ {th} nth step is equal to the sum of ways of reaching (n-1)^ {th} (n− 1)th step and ways of reaching (n-2)^ {th} (n−2)th step.
